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  1. #include <stdio.h>
  2. int a( int n ){
  3. 	if(n==1) return 2;
  4. 	else return 2*a(n-1)+2*a(n=1);
  5. }
  6. int main(void) {
  7. int n;
  8. scanf("%d", &n);
  9. printf("a(%d)の値は%d\n", n, a(n));
  10. return 0;
  11. }
  12.  
Success #stdin #stdout 0s 5288KB
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stdin
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2
stdout
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a(2)の値は8
https://ideone.com/5ENvFp
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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