#include <stdio.h>
// a[n] = -6a[n-1] - 9a[n-2], a[1]=1, a[2]=2 (再帰版)
int rec(int n){
if (n == 1){
return 1;
}
else if (n == 2){
return 2;
}
else{
return -6 * rec(n - 1) - 9 * rec(n - 2);
}
}
int main(void){
int n = 4;
printf("数列a%dの値は%d\n", n
, rec
(n
)); return 0;
}
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